What is (a) highest, and (b) lowest, resistance which can be obtained by combining Com resistors having the following resistances ?
What is (a) highest, and (b) lowest, resistance which can be obtained by combining Com resistors having the following resistances ?
4 Ω, 8 Ω, 12 Ω, 24 Ω
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(a) For obtaining the highest resistance by combining the given resistances, we must connect them in series.
We get,
R = 4 + 8 + 12 + 24 = 48 ohms
(b) For obtaining the lowerst resistance by combining the given resistances, we must connect them in parallel.
We get,
1/R = 1/4 + 1/8 + 1/12 + 1/24
On solving we get, R = 2 ohms
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