A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg. The area of cross-section
A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg. The area of cross-section of the piston carrying the load is 425 cm2 . What maximum pressure would the smaller piston have to bear?
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The maximum mass of a car that can be lifted, m = 3000 kg
Area of cross-section of the load-carrying piston, A = 425 cm2 = 425 × 10–4 m2
The maximum force exerted by the load,
F = mg = 3000 × 9.8 = 29400 N
The maximum pressure exerted on the load-carrying piston, P = F/A
= 29400/425 x 10-4 = 6.917 x 105Pa
Pressure is transmitted equally in all directions in a liquid. Therefore, the maximum pressure that the smaller piston would have to bear is 6.917 × 105 Pa.
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