The radius of the circle having centre at (2, 1), whose one of the chord is a diameter of the circle x^2 + y^2 – 2x – 6y + 6 = 0
The radius of the circle having centre at (2, 1), whose one of the chord is a diameter of the circle x 2 + y2 – 2x – 6y + 6 = 0 is
(1) 1
(2) 2
(3) 3
(4) √3
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