One of the diameters of the circles is given by x^2 + y^2 – 2x + 4y – 4 = 0,
One of the diameters of the circles is given by x2 + y2 – 2x + 4y – 4 = 0, is
(1) x – y – 3 = 0
(2) x + y – 3 = 0
(3) –x + y – 3 = 0
(4) x + y + 3 = 0
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The correct option
(1) x – y – 3 = 0
Equation of circle is x2 + y2 – 2x + 4y – 4 = 0
. .. Centre is (1, –2)
As we know the equation of diameter is passing through centre.
Now, taking option (1)
i.e., x – y – 3 = 0
=> 1 + 2 – 3 = 0 => 0 = 0
. .. It is a required equation of diameter.
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