If the lines 3x – 4y – 7 = 0 and 2x – 3y – 5 = 0 are two diameters of a circle of area 49 π sq. unit
If the lines 3x – 4y – 7 = 0 and 2x – 3y – 5 = 0 are two diameters of a circle of area 49 π sq. unit, the equation of the circle is
(1) x2 + y2 + 2x – 2y – 62 = 0
(2) x2 + y2 – 2x + 2y – 62 = 0
(3) x2 + y2 – 2x + 2y – 47 = 0
(4) x2 + y2 + 2x – 2y – 47 = 0
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