The point whose abscissa is equal to its ordinate and which is equidistant from the points (1, 0) and (0, 3) is
The point whose abscissa is equal to its ordinate and which is equidistant from the points (1, 0) and (0, 3) is
(1) (1, 1)
(2) (2, 2)
(3) (3, 3)
(4) (4, 4)
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(2) (2, 2)
Explanation
Let the point be (x, x) , so according to the condition (x–1)2 + (x –0)2 = (x –0)2 + (x –3)2
= –2x + 1 = –6x + 9 => x = 2
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