The de Broglie wavelength of a photon is twice the de Broglie wavelength of an electron. The speed of the electron is  ve=c/100. Then

(a) Ee/Ep=10-4

(b)  Ee/Ep =10-2

(c) Pe/meC=10-2

(d) Pe/meC=10-4

4 views

1 Answers

(b), (c)

(b)  Ee/Ep =10-2

(c) Pe/meC=10-2

4 views