150 mL of 0.5 N nitric acid solutions at 25.35^0C was mixed with 150 mL of 0.5 N sodium hydroxide solutions at the same temp.
150 mL of 0.5 N nitric acid solutions at 25.350C was mixed with 150 mL of 0.5 N sodium hydroxide solutions at the same temp. The final temperature was recorded to be 28.770C. Calculate the heat of neutralization of nitric acid with sodium hydroxide.
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Total mass of solution = 150 + 150 = 300 g
Q = Total heat produced
= 300 x (28.77-25.35) cal
=300 x 3.42= 1026 cal
Heat of neutralization = Q/150 x 1000 x 1/0.5 = 13.68 Kcal
Since heat is liberated, heat of neutralization should be negative. So heat of neutralization = -13.68 Kcal
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