An inductor-coil, a capacitor and an AC source of rms voltage 24V are connected in series.
An inductor-coil, a capacitor and an AC source of rms voltage 24V are connected in series. When the frequency of the source is varied, a maximum rms current of 6.0A is observed. If this inductor coil is connected to a battery of emf 12V and internal resistance 4.0Ω, what will be the current?
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Erms = 24V
r = 4Ω, Irms = 6A
R = E/I = 24/6 = 4Ω
Internal Resistance = 4Ω
Hence net resistance = 4 + 4 = 8Ω
∴ Current = 12/8 = 1.5A
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