The magnetic field due to the earth has a horizontal component of 26μT at a place where the dip is 60°.
The magnetic field due to the earth has a horizontal component of 26μT at a place where the dip is 60°. Find the vertical component and the magnitude of the field.
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δ(dip) = 60°
BH = Bcos 60°
=> B = 52 × 10–6 = 52μT
BV = Bsinδ = 52 × 10–6√3/2 = 44.98μT ≈ 45μT
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