The needle of a dip circle shows an apparent dip of 45° in a particular position and 53°
The needle of a dip circle shows an apparent dip of 45° in a particular position and 53° when the circle is rotated through 90°. Find the true dip.
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If δ1 and δ2 be the apparent dips shown by the dip circle in the 2⊥r positions, the true dip δ is given by
Cot2δ = Cot2δ1 + Cot2δ2
=> Cot2δ= Cot245° + Cot253°
=> Cot2δ = 1.56 => δ = 38.6 ≈ 39°
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