Derive the expression Kb = [M^+ ][OH^- ] / [MOH] for dissociation of a weak base MOH in water ,
Derive the expression Kb = [M+ ][OH- ] / [MOH] for dissociation of a weak base MOH in water , which is undergo complete dissociation in the solution.
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MOH -----> M+ + OH-
Initial conc Cx1 0 0
C-Cα Cα Cα
Kb = [H+ ][X- ] / [HX]
= Cαx Cα/C- Cα
=C2 α2 /C(1-α)
Kb=Cα2 /1-α
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