The pK a of a weak acid, HA, is 4.80. The pKb of a weak base, BOH is 4.78.
The pK a of a weak acid, HA, is 4.80. The pKb of a weak base, BOH is 4.78. The pH of an aqueous solution of the corresponding salt, BA, will be
(a) 9.22
(b) 9.58
(c) 4.79
(d) 7.01
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(d) : Given that pKa = 4.8 and pKb = 4.78
Therefore, pH = 7 + 1/2 (pK a – pKb )
= 7 + 1/2 (4.80 – 4.78) = 7.01
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