How much bacl2 would be required to make 250 ml of solution

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How much bacl2 would be required to make 250 ml of solution

How how much bacl2 would be needed to make 250 ml of solution having same concentration of a chlorine negative as the one containing 3.78 gram of NaCl per 100ml ?

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Salim Ahmed Kawsar · Answer 1 · Feb 05, 2023 15:29:48

Two solution of same concentration would mean that the molarity of both the solutions is equal. Therefore, first we need to calculate the molarity of NaCl solution.

Mass of NaCl = 3.78 g

Molar Mass of NaCl = 58.5 g/mol

Volume of NaCl Solution = 100 mL = (100 / 1000) L

(Molarity)_NaCl = Mass of NaCl in grams / (Molar Mass of NaClxVolume of solution in L)

(Molarity)_NaCl = (3.78 x 1000) / (58.5 x 100)

(Molarity)_NaCl = 0.65 mol/L

Now, (Molarity)_NaCl = (Molarity)_BaCl2

Mass of BaCl₂ = m g

Molar Mass of BaCl₂ = 208.33 g/mol

Volume of BaCl₂ solution = 250 mL = (250 / 1000) L

(Molarity)_BaCl2 = Mass of BaCl₂ in grams/(Molar Mass of BaCl₂xVolume of solution in L)

0.65 = (m x 1000) / ( 208.33 x 250) g

m = (0.65 x 208.33) / 4 g

m= 33.8 g

Hence, 33.8 g of BaCl₂ is required to make 250 ml of solution having same concentration of chloride as one containing 3.78g NaCl per 100ml.

How much bacl2 would be required to make 250 ml of solution

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