1 Answers
tan-1[tan3π/4] = tan-1(tan(π-π/4))
= tan-1(tan π/4)
Since tan-1(tanx) = x if x ∈ (-π/2,π/2)
Here π/4 ∈ (-π/2,π/2)
= π/4
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Answered
tan-1[tan3π/4] = tan-1(tan(π-π/4))
= tan-1(tan π/4)
Since tan-1(tanx) = x if x ∈ (-π/2,π/2)
Here π/4 ∈ (-π/2,π/2)
= π/4