1 Answers
The given function is cot(tan-1a+cot-1a).
∴cot(tan-1a+cot-1a)=cot(π/2) [as tan−1x+cot−1x=π/2]
=0
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Answered
The given function is cot(tan-1a+cot-1a).
∴cot(tan-1a+cot-1a)=cot(π/2) [as tan−1x+cot−1x=π/2]
=0