In a box there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
In a box there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
(a) 7/19 (b) 2/3 (c) 3/4 (d) 9/21
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(e) If the drawn ball is neither red nor green, then it must be blue, which can be picked in 7C1 = 7 ways. One ball can be picked from the total (8 + 7 + 6 = 21) in 21C1 = 21 ways.
Reqd probability = 7/21=1/3
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