From 5 different green balls, four different blue balls and three different red balls, how many combinations of balls can be chosen

Question

From 5 different green balls, four different blue balls and three different red balls, how many combinations of balls can be chosen

From 5 different green balls, four different blue balls and three different red balls, how many combinations of balls can be chosen taking at least one green and one blue ball?

Monjur Alahi

8 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Total combination of balls = 2¹²
Combination of balls with no green balls = 2⁷
Combination of balls with no blue balls = 2⁸
Combination of balls with no blue balls and no green balls = 2³

Required combination = 2¹²- 2⁷ - 2⁸ + 2³ = 3720

8 views Answered 2023-02-05 15:29