Air is pushed into a soap bubble of radius r to double its radius. If the surface tension of the soap solution is S, the work done in the process is 

(a) 8πr2

(b) 12πr2

(c) 16πr2

(d) 24πr2S.

5 views

1 Answers

The correct answer is (d) 24πr2S.

Explanation: 

The surface tension S is equal to surface energy per unit area, S = U/A 

→U = SA 

The total area of the soap bubble =2*4πr² =8πr² 

The total surface energy of the original bubble =8πr²S 

The total surface area of the expanded bubble = 2*4π(2r)² =32πr² 

The total surface energy of the expanded bubble =32πr²S 

The work done in the process = increase in the surface energy of the bubble =32πr²S - 8πr²S =24πr²S

5 views