If more air is pushed in a soap bubble, the pressure in it
If more air is pushed in a soap bubble, the pressure in it
(a) decreases
(b) increases
(c) remains same
(d) becomes zero.
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(a) decreases
Explanation:
The excess pressure (w.r.t. atmospheric pressure) inside a soap bubble is given as P'-P = 4S/R, {where P'-pressure inside the bubble, P- atmospheric pressure}
It is clear that the excess pressure inside is inversely proportional to the radius. As more air is pushed in a soap bubble its radius increases hence the excess pressure inside decreases.
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