Let X = {1, 2, 3, 4, 5}. The number of different ordered pairs (Y, Z) that can be formed such that Y ⊆ X, Z ⊆ X and Y ∩ Z is empty is

(a) 25 

(b) 53

(c) 52 

(d) 35

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1 Answers

(d) : X = {1, 2, 3, 4, 5}; Y ⊆ X , Z ⊆ X, Y ∩ Z = ϕ
Number of ways = 35.

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