Refer to the previous problem. Suppose, the goldsmith argues that he has not mixed copper or any other material with gold,
Refer to the previous problem. Suppose, the goldsmith argues that he has not mixed copper or any other material with gold, rather some cavities might have been left inside the ornament. Calculate the volume of the cavities left that will allow the weights given in that problem.
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Let the volume of the cavities be v,
The total volume of the ornament V =volume of gold+volume of cavities
=36/19.3 +v cm³
The volume of the water displaced is also V cm³
The mass of the water displaced =V*1 gram =V gram
The weight of the water displaced =Vg
Hence Vg=(36-34)g
→V=2 →36/19.3 +v =2
→v =2-36/19.3 =2-1.865
→v =0.135 cm³
→v =0.135 cm³
(Note: the result has some variation from the answer in the book which is 0.112 cm³)
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