The coordination number and the oxidation state of the element E in the complex.
The coordination number and the oxidation state of the element E in the complex [E(en)2(C2O4)]NO2(where (en) is ethylene diamine) are, respectively
(a) 6 and 3
(b) 6 and 2
(c) 4 and 2
(d) 4 and 3
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(a) : In the given complex [E(en)2(C2O4)] +NO2- ethylene diamine is a bidentate ligand and (C2O42–) oxalate ion is also bidentate ligand. Therefore coordination number of the complex is 6 i.e., it is an octahedral complex.
Oxidation number of E in the given complex is
x + 2 × 0 + 1 × (–2) = +1
Therefore, x = 3
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