A person sitting on the top of a tall building is dropping balls at regular intervals of one second.
A person sitting on the top of a tall building is dropping balls at regular intervals of one second. Find the positions of the 3rd, 4th and 5th ball when the 6th ball is being dropped.
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Height of fall of balls are given by the equation,
h=ut+½gt² =½gt² (Since u=0)
For the 3rd ball t=3 s, So h=½*9.8*9 =44.1 m below the top of the building.
For the 4th ball t=2 s, So h=½*9.8*4 =19.6 m below the top of the building.
For the 5th ball t=1 s, So h=½*9.8*1 =4.9 m below the top of the building.
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