How many moles of magnesium phosphate, Mg3 (PO4)2 will contain 0.25mole of oxygen atoms?
(a) 0.02
(b) 3.125 × 10–2
(c) 1.25 × 10–2
(d) 2.5 × 10–2 .


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(b) : 1mole of Mg3 (PO4 )2
=> 3moles of Mg atom + 2 moles of P atom + 8 moles of O atom
8 moles of oxygen atoms are present in = 1mole of Mg3 (PO4)2
0.25mole of oxygen atoms are present in = (1 x 0.25)/8

= 3.125 × 10–2moles of Mg3 (PO4 ) 2.

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