Let the no. of girls be 5x
No. of boys=7x
According to the question
5x+8=7x
7x-5x=8
2x=8
x=8/2
x=4
No. of girls=5*4=20
no. of boys=7*4 or 5*4+8=28
Hence the total strength of the class is 20+28=48
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(b) (i) Oviduct or fallopian tubes...
Leaving one seat vacant between two boys may be seated in 4! ways. Then at remaining 5 seats, 5 girls any sit in 5! ways. Hence the required number =...
(d) Assume the 2 given students to be together (i.e one].
Now there are five students.
Possible ways of arranging them are = 5! = 120
Now, they (two girls) can arrange themselves...