In how many ways can 5 boys and 5 girls be seated at a round table no two girls may be together ?
In how many ways can 5 boys and 5 girls be seated at a round table no two girls may be together ?
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Leaving one seat vacant between two boys may be seated in 4! ways. Then at remaining 5 seats, 5 girls any sit in 5! ways. Hence the required number = 4! × 5!
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