The amount of nitric acid required to oxidize 127 g of I2 to I2O5 will be? Assume that HNO3, gets converted to NO2.
The amount of nitric acid required to oxidize 127 g of I2 to I2O5 will be? Assume that HNO3, gets converted to NO2.
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The balanced chemical equation is given by
I2 + 10HNO3 = I2O5 + 10NO2 + 5H2O
Here 127 x 2 gm I2 is required to oxidise 63x10 gm of HNO3.
So in 127 gm I2 is will oxidise (63x10)/2 = 315gm
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