There is a narrow rectangular plot, reserved for a school, in Mahuli village. The length and breadth of the plot are in the ratio 11:4.

There is a narrow rectangular plot, reserved for a school, in mahuli village. the length and breadth of the plot are in the ratio 11:4. 

let the common multiple be x 

the length will be 11x 

breadth = 4x 

Perimeter = 2( L + B ) 

=2(11x+4x) 
= 2*15x
=30x 

At the rate Rs 100 per meter 

30x * 100 = 3000x 
3000x= 75000 
3x=75 
x=25 

11x = 11*25 = 275m 
4x=4*25 = 100 m 

275m & 100m are the dimensions of the Plot

Let the common ratio between the length and breadth of the rectangular plot be x. Hence, the length and breadth of the rectangular plot will be 11x m and 4x m respectively.

Perimeter of the plot = 2(Length + Breadth)

= [2(11x + 4x)]m = 30xm

It is given that the cost of fencing the plot at the rate of Rs 100 per metre is Rs 75, 000.

∴ 100 × Perimeter = 75000

100 × 30x = 75000

3000x = 75000

Dividing both sides by 3000, we obtain

x = 25

Length = 11x m = (11 × 25) m = 275 m

Breadth = 4x m = (4 × 25) m = 100 m

Hence, the dimensions of the plot are 275 m and 100 m respectively