The activation energy of a reaction is 94.14 KJ/mol and the value of rate constant at 40º C is 1.8 x 10-1 sec-1.
The activation energy of a reaction is 94.14 KJ/mol and the value of rate constant at 40º C is 1.8 x 10-1 sec-1. Calculate the frequency factor A
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Given, Ea = 94.14 x 103 J mol-1, T = 40 + 273 =313 K, K = 1.8 x 10-1 sec-1
By using,
A = antilog (10.9635) = 9.194 x 1010 sec-1
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