What is the quantity of electricity in coulombs needed to reduce 1 mol of cr2o27 ? Consider the reaction:
What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr2O72-? Consider the reaction:
Cr2O72- +14H ++6e --> 2Cr3+ +8H2O
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The given reaction is as follows:
Cr2 O72- + 14H+ + 6e- → Cr3+ + 8H2O
Therefore, to reduce 1 mole of Cr2 O72-, the required quantity of electricity will be:
=6 F
= 6 × 96487 C
= 578922 C
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