A cubic solid is made of two elements P and Q. Atoms of Q are at the corners of the cube and P at the body-centre. What is the formula of the compound? What are the coordination numbers of P and Q? 

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2 Answers

It is given that the atoms of Q are present at the corners of the cube.

Therefore, number of atoms of Q in one unit cell =8x1/8=1

It is also given that the atoms of P are present at the body-centre.

Therefore, number of atoms of P in one unit cell = 1 

This means that the ratio of the number of P atoms to the number of Q atoms, P:Q = 1:1 

Hence, the formula of the compound is PQ. The coordination number of both P and Q is 8.

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The atom at the corner makes \(\frac{1}{8}\) contribution while atom at body centre makes 1 contribution to the unit cell.

No. of atoms of Q per unit cell = 8 × \(\frac{1}{8}\) = 1

No. of atoms of P per unit cell = 1 × 1 = 1

Therefore, formula of the compound is PQ.

The atom at the body centre would be in contact with all the atoms at the corners. Hence, the coordination number of P is 8.

Similarly, the coordination number of Q is 8 because it is shared by 8 other atoms.

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