Calculate the number of atoms in a cubic unit cell having one atom on each corner and two atoms on each body diagonal.
Calculate the number of atoms in a cubic unit cell having one atom on each corner and two atoms on each body diagonal.
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8 corner × 1/8 atom per unit cell = 1 atom
There are four body diagonals in a cubic unit cell and each has two body centre atoms.
So, 4 × 2 = 8 atoms therefore, total number of atoms per unit cell = 1 + 8 = 9.
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No. of particles due to corners = 8 x 1/8 = 1
There are four body diagonals in a cube and a particle present on the body diagonal is completely present in the unit cell itself.
No. of particles due to body diagonal = 4 x 2 = 8
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