Silver forms ccp lattice and X-ray studies of its crystal show that the edge length of its unit cell is 408.6 pm
Silver forms ccp lattice and X-ray studies of its crystal show that the edge length of its unit cell is 408.6 pm. Calculate the density of silver (Atomic wt. = 107.9u).
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Solution :
Silver forms cubic close packing (ccp) , therefore the number of silver atoms per unit cell z=4
Molar mass of silver M=107.9 gmol−1 = 107.9×10−3kgmol−1
Edge length of unit cell a=408.6 pm = 408.6×10−12
Density d=(z.M)/(a3.NA)
d=4×(107.9×10−3kgmol−1)/(408.6×10−12m)3(6.022×1023mol−1)
=10.5×103kgm−3
d=10.5gcm−3
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