What are the co-ordination numbers of octahedral voids and tetrahedral voids ?
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Why the bond angle H-N-H is 1070 and H-O-H is 1050, instead of 109028’ characteristic of tetrahedral structure?
Lone pair lone pair repulsion in H2O has more magnitude than that of lone pair bond pair repulsion in NH3.
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What is the co-ordination number of cation and anion in Caesium chloride (bcc arrangement) ?
your the answer 8 and 8.
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A compound is formed by two elements M and N. The element N forms ccp and atoms of M occupy 1/3rd of tetrahedral voids.
The ccp lattice is formed by the atoms of the element N. Here, the number of tetrahedral voids generated is equal to twice the number of atoms of the element N. According...
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Explain the following : (i) CO is stronger ligand than NH3. (ii) Low spin octahedral complexes of nickel are not known.
(i) CO has high value of crystal field splitting energy than Cl. (ii) Ni has d8 conguration which does not affect by field strength of ligand. (iii) In this case, Ti+3 has...
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In a compound, atoms of element Y form ccp lattice and those of element X occupy 2/3^rd of tetrahedral voids.
(b) : Number of Y atoms per unit cell in ccp lattice (N) = 4 number of tetrahedral voids = 2N = 2 × 4 = 8 number of tetrahedral voids occupied by...
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For the octahedral complexes of Fe^3+ in SCN– (thiocyanato-S) and in CN– ligand environments,
Approximately 4
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If the unit cell of a mineral has cubic close packed (ccp) array of oxygen atoms with m fraction of octahedral holes occupied by aluminium
The correct answer is (A) In ccp, O2– ions are 4. Hence total negative charge = –8 Let Al3+ ions be x, and Mg2+ ions be y. Total positive charge = 3x + 2y ⇒ 3x...
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In which of the following octahedral complexes of Co (At. no. 27), will the magnitude of Δoct be the highest?
(b) : Strong field ligand such as CN–, usually produce low spin complexes and large crystal field splittings. H2O is a weaker field ligand than NH3 and C2O42– therefore Δoct [Co(H2O)6]3+ < Δoct...
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The average of five numbers is 281. The average of the first two numbers is 280 and the average of the last two numbers is 178.5.
(a) Assume the third number = x According to question 2 × 280 + x + 178.5 × 2 = 281 × 5 or, 560 + x + 357 = 1405 or, x +...
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The sum of five numbers is 290. The average of the first two numbers is 48.5 and the average of last two numbers is 53.5.
(e) Third number = 290 – (48.5 × 2) – (53.5 × 2) = 290 – 97 – 107= 86
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