3 Answers
Each oxygen in a peroxide is assigned a formal charge of -1. Since sodium peroxide is neutral overall, each sodium atom is assigned an oxidation number of +1.
4 views
Answered
Let x be the oxidation station of sodium in Na2O2.
therefore
Na2= 2x & O2= (-1)2
= 2x+(-2)=0
=2x-2=0
x=(-2)/2
x=(-1)
4 views
Answered
Let the oxidation state of Na be y.
In case of peroxides, the oxidation state of oxygen is -1.
2(y) + 2(-1) = 0
2y – 2 = 0
2y = 2
Y = +1
Y = +1
4 views
Answered