A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag.

Question

A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag.

A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red ? (ii) not red?

Share with your friends

Talk Doctor Online in Bissoy App

Salim Ahmed Kawsar · Answer 1 · Feb 05, 2023 15:29:48

Solution: Total number of outcomes = 3 + 5 = 8

Number of favourable outcomes = 3

Hence;

P(Red) = 3/8

(ii) not red?

Solution:

P( not Red) = 1-3/8 = 5/8

Salim Ahmed Kawsar · Answer 2 · Feb 05, 2023 15:29:48

A bag contains 3 red balls, 5 black balls.

Totally there are 8 balls.

∴ n(S) = 8

i) Possibility that the red ball drawn, n(E) = 3

∴ Probability, P(E) = \(\frac{n(E)}{n(S)} = \frac{3}{8}\)

(ii) Possibility that the 1 black ball drwn is n(F) = 5

∴ Probability, P(F) = \(\frac{n(F)}{n(S)} = \frac{5}{8}\)

Salim Ahmed Kawsar · Answer 3 · Feb 05, 2023 15:29:48

Total number of balls :- 8

Red Balls = 3

Not Red Balls = 5

(i) P (red) = 3/8

(ii) P(not red) = 5/8

A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag.

3 Answers