It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992.

Monjur Alahi

It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?


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Salim Ahmed Kawsar

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1 – 0.992 = 0.008

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Salim Ahmed Kawsar

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No. of students in the group is 3. 

Probability of 2 students not having the same birthday is 0.992. 

Then possibility of having the same birthday = 1 – 0.992 = 0.008.

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Salim Ahmed Kawsar

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Let E be the event of 2 students having the same birthday and _E’ be the event of not getting the same birthday 

Given: 

P(E) = 0.992 

We know that, 

P(E) + P(E’) = 1 

∴ P(E’) = 1 – P(E) 

= 1 – 0.992 

= 0.008

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