ABCD is a trapezium in which AB || DC. The ratio of AB to DC is 2 : 1, and the distance between AB and DC is 20 cm. If the area of the trapezium is 720 cm2, then the length of AB is?

36 cm
42 cm
48 cm
54 cm

LohaHridoy

7 views

2025-01-04 04:42

1 Answers

AhmedNazir

Option 3 : 48 cm

Given:

ABCD is a trapezium.

AB || CD,

Ratio of AB to DC = 2 : 1

Distance between AB and CD = 20 cm

Area of trapezium = 720 cm²

Concept used:

Area of trapezium = 1 / 2 (sum of parallel sides) × height

Calculation used:

Let AB = 2x , CD = x

Area of trapezium = 720 cm2

⇒ 1 / 2 × (2x + x) × 20 = 720 cm2

⇒ 1 / 2 × (3x) × 20 = 720 cm²

⇒ x = 24 cm

∴ The length of AB = 2x = 2 × 24 = 48 cm

∴ Option 3 is correct.

7 views Answered 2022-09-04 04:29

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