Among five rods, P, Q, R, S and T, the weight of T is 20 kg. The weight of S is half the weight of P. The weight of Q is one-fourth the weight of P. R's weight is twice the weight of Q. The weight of P is twice the weight of T. Which rod is the lightest among all?

Question

Among five rods, P, Q, R, S and T, the weight of T is 20 kg. The weight of S is half the weight of P. The weight of Q is one-fourth the weight of P. R's weight is twice the weight of Q. The weight of P is twice the weight of T. Which rod is the lightest among all?

P
S
Q
R

LohaHridoy

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2025-01-04 04:42

1 Answers

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AhmedNazir · Accepted Answer · 2022-09-04T04:29:57+06:00

Option 3 : Q

Given:

The weight of T = 20 kg.

Calculation:

1. The weight of P is twice the weight of T:

P = 2 × T

P = 2 × 20

P = 40 kg

2. The weight of S is half the weight of P:

S = P ÷ 2

S = 40 ÷ 2

S = 20

3. The weight of Q is one-fourth of the weight of P:

Q = P ÷ 4

Q = 40 ÷ 4

Q = 10 kg

4. R's weight is twice the weight of Q:

R = 2 × Q

R = 2 × 10

R = 20 kg

Rod "Q" is the lightest among all.

Hence, The correct answer is "Q".