Two containers A and B contain 50 gm of ice at 0°C and 50 gm of water at 0°C respectively. If both the containers are kept in the freezer of a refrigerator and allowed to reach thermal equilibrium, which of the following statements will be true?

B will lose more heat than A
A will lose more heat than B
Both A and B will lose equal heat
Which of them will lose more heat cannot be determined

LohaHridoy

13 views

2025-01-04 04:42

1 Answers

AhmedNazir

Option 2 : A will lose more heat than B

Concept :

Latent heat:

It is the heat energy that is given to change the state of a substance.
'Latent' means' hidden' i.e. heat in the substance undergoing the change of state, and does not change its presence by raising the temperature.
Latent heat does not raise the temperature of the substance
But the latent heat has always to be supplied to change the state of a substance.

Explanation

The latent heat supplied is used up in overcoming the forces of attraction between the particles of a substance during the change of state.
The latent heat does not increase the kinetic energy of the particles of the substance.
Since, there is no increase in the kinetic energy of the particles, the temperature of a substance does not rise during the change of state.
Ice will lose more heat as it is the heat energy that prevents the temperature from further cooling.
Heat energy does not warm the temperature but rather stops further cooling and this happens at thermal equilibrium.
So, the correct answer is A will lose more heat than B.

About 334 J of energy is required to melt 1g of ice at 0°C, which is the latent heat of melting.

13 views Answered 2022-09-04 04:29

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