If ab < 0 and the point (a, b) lies in the 2nd quadrant in which the point (b/2, -3a/5) lies is:?
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Option 1 : I
∵ ab < 0
⇒ either a < 0 or b < 0.
We are given that (a, b) lies in 2nd quadrant that means a < 0 and b > 0.
⇒ b/2 > 0 and –a > 0 and so -3a/5 > 0
⇒ (b/2, -3a/5) lies in 1st quadrant.
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