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Option 2 : Only I and II
From statement I and II
Probability of first ball to be blue = 6C1/18C1
Probability of the second ball turns out to be blue with the given condition = 10C1/22C1
Required probability = (6C1/18C1) × (10C1/22C1) = 5/33
∴ Only I and II are required and statement III do not give any proper relation and will not help in solving
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