1 Answers

Option 2 : Only I and II

From statement I and II

Probability of first ball to be blue = 6C1/18C1

Probability of the second ball turns out to be blue with the given condition = 10C1/22C1

Required probability = (6C1/18C1) × (10C1/22C1) = 5/33

∴ Only I and II are required and statement III do not give any proper relation and will not help in solving
5 views

Related Questions