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Doctors Medicines MCQs Q&A

  1. 1 only
  2. 2 only
  3. Both 1 and 2
  4. Neither 1 nor 2
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1 Answers

Option 3 : Both 1 and 2

Construct a perpendicular from A to the line CF, Let it meet BE at O and CF at P

Similarly a perpendicular from D is drawn to the line CF, let it meet BE and CF at R and S

In triangle ABO and ACP

∠A is common and ∠O = ∠P = 90°

ABO ∼ ACP

∴ AB/AC = AO/AP

In triangle DRE and DSF

∠D is common and ∠R = ∠S = 90°

DRE ∼ DSF

∴ DE/DF = DR/DS

Parallel lines are equally spaced

∴ AO = DR and AP = DS

∴ AB/AC = DE/DF

So statement 1 is correct

AB/ (AC - AB) = DE/ (DF - DE)

AB/BC = DE/EF

∴ AB × EF = BC × DE

So statement 2 is also correct

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