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Option 1 : 9π cm2
Let the radius of the bigger circle be R cm and radius of the smaller circle be r cm.
⇒ PQ = 2√(Rr)
⇒ 6 = 2√(Rr)
⇒ Rr = 9 cm
The radius of the semicircle made on diameter AB = R + r
⇒ Area of shaded portion = π/2(R + r)2 – Area of the semicircle of radius R – Area of the circle of radius r
⇒ Area of shaded portion = π/2(R + r)2 – π/2 × R2 – π/2 × r2
⇒ Area of shaded portion = π/2
⇒ Area of shaded portion = π/2 × 2Rr
∴ Area of shaded portion = 9π cm2
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