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Option 1 : 23%
When T remains constant,
s₁V₁ ² = s₂ V₂ ²
so, s₂/s₁=(V₁/V₂)²=(1/0.9)²=1.23
we know that I ₂ ∝ s V
I’₂ / I₂ =(s₂V₂ / s₁V₁) = 1.2 × 0.9 = 1.107
Now, Cu losses are nearly proportional to I₂²
∴ Cu loss in the 2nd case/ Cu loss in the 1st case = (I ′₂)²/(I₂)² = (1.1072)2 = 1.23
Reduction of 10% in line voltage causes about 23% increase in Cu losses.
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