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Option 3 : Both 1 and 2

We can write,

⇒ XYZ = 100X + 10Y + Z

⇒ YZX = 100Y + 10Z + X

⇒ ZXY = 100Z + 10X + Y

Sum of the numbers

= 100X + 10Y + Z + 100Y + 10Z + X + 100Z + 10X + Y

= 111X + 111Y + 111Z

= 111(X + Y + Z)

Hence, the sum of the numbers is divisible by both 111 and (X + Y + Z)

∴ Statement 1 and 2, both are correct.
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