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Option 1 : \(k \ne \frac {15} {2}\)
Given:
2x + 3y = 2k and 5x + ky = -2 has a unique solution
Concept Used:
If 2 lines (ax + by = c) and (px + qy = r) have a unique solution, then
(a/p) ≠ (b/q)
Calculations:
2x + 3y = 2k and 5x + ky = -2 has a unique solution
⇒ (2/5) ≠ (3/k)
⇒ k ≠ (5 × 3)/2
⇒ k ≠ 15/2
∴ The value of k is not equal to 15/2.
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