1. \(k \ne \frac {15} {2}\)
  2. k ≠ 4
  3. k ≠ 8
  4. \(k \ne \frac {13} {2}\)
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1 Answers

Option 1 : \(k \ne \frac {15} {2}\)

Given:

2x + 3y = 2k and 5x + ky = -2 has a unique solution

Concept Used:

If 2 lines (ax + by = c) and (px + qy = r) have a unique solution, then

(a/p) ≠ (b/q)

Calculations:

2x + 3y = 2k and 5x + ky = -2 has a unique solution

⇒ (2/5) ≠ (3/k)

⇒ k ≠ (5 × 3)/2

⇒ k ≠ 15/2

∴ The value of k is not equal to 15/2.

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