Each of the questions below consists of a question and three statements number I, II and III given below it. You have to decide whether the data provided in the statement are sufficient to answer the question. Find the percentage of impurity in the mixture. I. A discount vendor professes to sell his at the cost price and mixes with impurity and thereby gain 25%. II. If in 45 kg of mixture, 5/2 times quantity of impurity is equal to 150% of 2/3 of the quantity of whole mixture. III. The ratio of quantity of pure wheat in the mixture to the total quantity of the mixture in 3 : 5. (Mixture is made of pure wheat and impurity)?

Question

Each of the questions below consists of a question and three statements number I, II and III given below it. You have to decide whether the data provided in the statement are sufficient to answer the question. Find the percentage of impurity in the mixture. I. A discount vendor professes to sell his at the cost price and mixes with impurity and thereby gain 25%. II. If in 45 kg of mixture, 5/2 times quantity of impurity is equal to 150% of 2/3 of the quantity of whole mixture. III. The ratio of quantity of pure wheat in the mixture to the total quantity of the mixture in 3 : 5. (Mixture is made of pure wheat and impurity)?

Only I alone is sufficient.
Only II alone is sufficient.
Only III alone is sufficient.
Either of them alone is sufficient.
All I, II and III together is sufficient.

LohaHridoy

6 views

2025-01-04 04:42

1 Answers

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AhmedNazir · Accepted Answer · 2022-09-04T04:29:57+06:00

Option 4 : Either of them alone is sufficient.

From I:

Let CP of 1 kg of pure wheat = Rs. 1

Then SP of kg of mixture = Rs. 1 and gain = 25%

CP of 1 kg of mixture = 1 × 100/125 = Rs. 4/5

Ratio of wheat to impurity = 4/5 : 1/5 = 4 : 1

Percentages impurity = 1/ (4 + 1) × 100 = 20%

Hence, statement I alone is sufficient.

From II:

Amount of mixture = 45 kg and amount of impurity is z kg.

Given –

⇒ 5/2 × z = 150% of 2/3 × 45

⇒ z = (150 × 2 × 45 × 2)/ (100 × 3 × 5)

⇒ z = 18

% impurity = 18/45 × 100 = 40%

Hence, statement II alone is sufficient.

From III:

Let total quantity of mixture = 5z and quantity of pure wheat = 3z.

Quantity of impurity in the mixture = 5z – 3z = 2z

% impurity = 2z/5z × 100 = 40%

Hence, statement III alone is sufficient.