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Option 2 :    B, C and F

Initially, each has a pack of 10 cards.

A B C D E F
10 10 10 10 10 10

F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B

A B C D E F
8 13 12 10 10 7

B gives 6 to D who passes on 1 to E

A B C D E F
8 7 12 15 11 7

Total cards possessed by D and E = 15 + 11 = 26

This number is same as the total cards possessed by B, C and F.

Hence, option 2 is the correct answer.

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